"Larry Goldstein, David Lay, David Schneider. 18. Ax = 2; the midpoints are .1, .3, .
5, .7, .9 Area = 0.2 Vl-(.l)2 Wl-(-3)2 +Vl-(-5)2 + Vl-(-7)2 +Vl-(.9)2 .79300 J 2(.
79300) = 1.586. The error is ... Thus, [/(*o) + f(*i ) + .-+ f(xn-i )]Ax = [approximation
given by the Riemann sum with left endpoints] < A < [approximation given by the
Riemann sum with right endpoints] = + /(jt2) + ... + /(jtn)]Ax. 28. Consider the
subinterval from t ..."